1a. Olaf is stand on a sheet of ice the covers the football stadium parking lot of in Buffalo, brand-new York; there is negligible friction in between his feet and the ice. A friend throws Olaf a ball of mass 0.350kg that is traveling horizontally in ~ 12.2m/s . Olaf's massive is 65.3kg. If Olaf captures the ball, v what rate vf carry out Olaf and also the ball relocate afterward?
0.35 kg(12.2 m/s) + 0 m/s(65.3 kg) = (65.3+0.35) kg*vf
1b. Olaf is standing on a sheet of ice the covers the football stadium parking many in Buffalo, brand-new York; there is negligible friction in between his feet and also the ice. A friend throws Olaf a sphere of mass 0.350kg that is travel horizontally at 12.2m/s . Olaf's mass is 63.3kg. If the round hits Olaf and also bounces turn off his chest horizontally at 9.00m/s in the opposite direction, what is his rate vf after ~ the collision?
0.35(12.2) + (-9)(0.35+63.3)=(63.3)(vf)
vf = -568.58/63.3
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· 8y · edited 8y
The first one watch good! Take one more look in ~ what her answer come 1b means in English - you stated that if Olaf records the ball he slides slowly backward, yet if it bounces off him he flies forward very quickly.
You are watching: If olaf catches the ball, with what speed vf do olaf and the ball move afterward?
The trouble is the term with the ball's last velocity - all the initial velocities must be ~ above one side and also all the last velocities on the other. Also, the sphere flies backwards by itself, not with Olaf, so the term should have only the ball's mass.
The setup have to be 0.35(12.2) + 65.3(0) = 0.35(-9) + 65.3(vf)
This leads to response of 0.117, an interpretation Olaf slides backward much faster than he did in 1a. That renders sense because some that the momentum in the mechanism is currently in the round travelling away from Olaf. That takes much more energy to avoid the ball and then propel it in the various other direction than it go to just stop it.
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